factorise 2 2 СА X x +13X+32 Б - чу Я ч + 3 в geg 2. с C БX + 2X— 2Г5
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Correct option is
D
(x+1)(x+2)(x+10)
The value of x
3
+13x
2
+32x+20 is
x
3
+x
2
+12x
2
+12x+20x+20
=x
2
(x+1)+12x(x+1)+20(x+1)
=(x−1)(x
2
+12x+20)
=(x−1)(x
2
+10x+2x+20)
=(x+1)[x(x+10)+2(x+10)]
=(x+1)(x+2)(x+10)
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