Question

factorise 2√2a^3+16√2b^3+c^3-12abc

Answer 1

x³+y³+z³+3xyz=

(x+y+z)(x²+y²+z²-xy-zx-yz)

Setting x=a√2,y=b√8,z=c,we have it equal to

(a√2+b√8+c)(2a²+8b²+c²-4ab-ac√2-bc√8)

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Answer 2

Answer of your question is in the attachment.

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