Math, asked by mukeshanju30, 11 months ago

Factorise: 2√2a^3-3√3b^3​

Answers

Answered by gourirupa
6

Answer: (a√2 -  b√3)(2a + ab√6 + 3b)

Step-by-step explanation:

2√2a³ - 3√3b³

=> (√2)³a³ - (√3)³b³

=> (a√2)³ - (b√3)³

By the formula a³ - b³ = (a - b)(a² + ab + b²) , we get :-

=> (a√2 - b√3)((a√2)² + (a√2)(b√3) + (b√3)²)      

=> (a√2 -  b√3)(2a + ab√6 + 3b)

Answered by Anonymous
7

(a√2-b√3)(2a+ab√6+3b)

2√2a3 - 3√3b3

(√2)3a3 - (√3)3b3

(a√2)3 - (b√3)3

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