Question

factorise 2√2a^3+8b^3-27c^3+18√2abc
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Answer 1

Answer:

2.828a^3+8b^3-27c^3+25.452abc

Answer 2

(√2a+ 2b -3c)(2a² + 4b² + 9c² - 2√2ab + 6bc + 3√2a)

Step-by-step explanation:

2√2a³+8b³-27c³+18√2abc

We know that,

a³+b³+c³- 3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)

From the given equation we know that

a = √2a ,  b = 2b and c = -3c, hence we expand it as,

= (√2a)³+(2b)³+(-3c)³ - 3(√2a)(2b)(-3c)

= (√2a+2b-3c)[(√2a)²+(2b)²(-3c)²-(√2a)(2b)-(2b)(-3c)-(-3c)(√2a)

= (√2a+ 2b -3c)(2a² + 4b² + 9c² - 2√2ab + 6bc + 3√2a)

To Learn More......

1. Factorise:

343p^3 - 1331p^3

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2. Factorise 8a^3-b^3-64c^3-24abc

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