factorise 2√2a^3+8b^3-27c^3+18√2abc
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hey frnd i will give ur ans u tell me wrng ya wrt
2√2a^3+8b^3 -27c^3+18√2abc
=(√2a)^3+(2b)^3 +(-3c)^3-3(√2a)(2b)(-3c)
=(√2a + 2b -3c)(2a^2 + 4b^2 + 9c^2 - 2√2ab + 6bc + 3√2ac)
2√2a^3+8b^3 -27c^3+18√2abc
=(√2a)^3+(2b)^3 +(-3c)^3-3(√2a)(2b)(-3c)
=(√2a + 2b -3c)(2a^2 + 4b^2 + 9c^2 - 2√2ab + 6bc + 3√2ac)
laxmikant6:
heyyyy
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