Question

factorise 2√2x^3+3✓3x^3+✓5(5-3✓6xy)

Answer 1

   22√x3 + 33√y3 + 5√(5 − 36√xy)=22√x3 + 33√y3 + 55√ − 330−−√xy=(2√x)3 + (3√y)3 + (5√)3 − 3(2√x)(3√y)(5√)=[2√x + 3√y + 5√][(2√x)2+(3√y)2+(5√)2−(2√x)(3√y)−(3√y)(5√)−(5√)(2√x)]=(2√x+3√y+5√)(2x2+3y2+5−6√xy−15−−√y−10−−√x)Using identity :a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)