Factorise (2−)^3+(−)^3+(−2)^3
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Answered by
2
Answer:
Let p(x)=2x
3
−3x
2
−3x+2$
p(−1)=0
Therefore, (x+1) is one of the factor.
The other factor is 2x
2
−5x+2
⇒2x
2
−x−4x+2
⇒x(2x−1)−2(2x−1)
⇒(2x−1)(x−2)
⇒2x
3
−3x
2
−3x+2=(x+1)(2x−1)(x−2)
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Answered by
1
Answer:
the above answer is correct dear friend
Step-by-step explanation:
have a great day ahead
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