Question

factorise -2√3x2+5x-4√3​

Answer 1

Answer:

$2 \sqrt{3} {x}^{2} + 5x - 4 \sqrt{3} = 0$

$= > 2\sqrt{3} {x}^{2} + 8x - 3x - 4 \sqrt{3} = 0$

$= > 2x( \sqrt{3} x + 4) - \sqrt{3} ( \sqrt{3} x + 4) = 0$

$= > ( \sqrt{3} x + 4)(2x - \sqrt{3} ) = 0$

$= > \sqrt{3} x + 4 = 0 \: or \: 2x - \sqrt{3} = 0$

$= > x = - \frac{4}{ \sqrt{3} } \: or \: \frac{ \sqrt{3} }{2}$