Math, asked by maahipatel, 11 months ago

Factorise: 2-50y^2. Please help me in solving this question. Its urgent

Answers

Answered by darknight07
1

hey buddy,

here is your ans..

2 -  {50y}^{2}  = 0 \\  - 50 {y}^{2}  =  - 2 \\ y {}^{2}  =  \frac{ - 2}{ - 50}  \\ y =  \sqrt{ \frac{1}{25 } }

I hope it helps you

thank you

have a great evening..


maahipatel: Is this answer for a 9th grader?
darknight07: yup mate. you can apply this..
maahipatel: Okay thankyou
darknight07: my pleasure mate.
Answered by Anonymous
1

Step-by-step explanation:

Rearranging the given expression: 2-50y^2

We know that a^2-b^2= (a+b)(a-b)

Applying the identity:

2-50y^2 = (√2)^2-50y^2

=(√2+50y)(√2-50y)


darknight07: bro the 2-50y² you can't write it as 2²-50y².. therefor the identity of a²+b² will not applied
darknight07: I mean a²-b²
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