Question

Factorise: 2(ab+cd)-a2-b2+c2+d2 pls answer fast​

Answer 1

Answer:

Hope it helps

Step-by-step explanation:

Answer 2

ANSWER:

Using identity : (m + n)² = m² + n² + 2mn

                           (m - n)² = m² + n² - 2mn

= 2(ab + cd) - a² - b² + c² + d²

= 2ab + 2cd - a² - b² + c² + d²

= -(a² + b² - 2ab) + (c² + d² + 2cd)

= (c + d)² - (a + b)²

= (c + d - a - b)(c + d + a + b)

HOPE THIS HELPS YOU.........

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