Question

factorise ;ɑ²+b²−c²−d²−2ab+2cd​

Answer 1

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Answer 2

Answer:

a 2+b 2 −c 2 −d 2+2ab−2cd

=(a 2+b 2+2ab)−(c 2+d 2+2cd)

=(a+b) 2−(c+d) 2[∴a 2−b 2 =(a+b)(a−b)]

=((a+b)−(c+d))((a+b)+(c+d))

=(a+b−c−d)(a+b+c+d)