Question

factorise 2 lCube + 432 m cube​

Answer 1

Step-by-step explanation:

which is the required ans.

Answer 2

Answer:

$2(l+6m)(l^{2}-6ml+36m^{2})$

Step-by-step explanation:

As per the given equation from the question,

We have to factorise  $2l^{3}+432 \ m^{3}$ that is we have to write this equation in its simplest form.

So,

$2l^{3}+432 \ m^{3}$

$2(l^{3}+216m^{3})$

$2(l^{3}+(6m)^{3})$

The above equation is the cubic identity of mathematics,

According to that equation,

$( \ a^{3}+b^{3} \ )=(a+b)(a^{2}-ab+b^{2})$

So we can write,

$2(l^{3}+(6m)^{3})=2(l+6m)(l^{2}-6ml+(6m)^{2})$

                 $=2(l+6m)(l^{2}-6ml+36m^{2})$

Hence, the required factor is $2(l+6m)(l^{2}-6ml+36m^{2})$.