Factorise 2(p+q) sq -7(p+q) +6
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2(p+q)² - 7(p+q) + 6
/* Splitting the middle term,we get */
= 2(p+q)² - 4(p+q) - 3(p+q) + 6
= 2(p+q)[ p+q - 2] - 3( p + q - 2 )
= (p+q-2)[2(p+q)- 3]
= (p+q-2)( 2p+2q-3)
Therefore.,
2(p+q)² - 7(p+q) + 6= (p+q-2)( 2p+2q-3)
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