factorise 2×root2 x^3 + 27y^3
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Answer:
2√2x³+27y³
Step-by-step explanation:
a³+ b³ = (a + b) (a² - ab + b² ).
so,
(2√2x+27y)(2√2²-2√2×27y+27²)
(2√2x + 27y)(8-54√2+729) = (737-54√2)(2√2x+27y)
please solve the latter part it must be easy
thank you
hope you get good marks in your exam!
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