Question

factorise
2 (x+2y)^2 - 5 (x+2y)+2​

Answer 1

Answer:

2 (x + 2y) 2 – 5 (x + 2y) + 2

Let x + 2y =a, then

2a2 – 5a + 2

⇒ 2a2 – a – 4a + 2

= a (2a – 1) – 2 (2a - 1)

= (2a – 1) (a – 2)

= {2(x + 2y -1)} {(x + 2y) – 2}

= (2x + 4y – 2) (x + 2y - 2)

Step-by-step explanation:

Answer 2

Given,

2 (x + 2y)² – 5 (x + 2y) + 2

To find,

Factorisation

Solution,

2 (x + 2y)² – 5 (x + 2y) + 2

Let x + 2y =a, then

2a² – 5a + 2

⇒ 2a² – a – 4a + 2

= a (2a – 1) – 2 (2a - 1)

= (2a – 1) (a – 2)

= {2(x + 2y -1)} {(x + 2y) – 2}

= (2x + 4y – 2) (x + 2y - 2)

So, 2 (x + 2y)² – 5 (x + 2y) + 2 factorises to (2x + 4y – 2) (x + 2y - 2)