Question

factorise √2+x^3-3√3y^3+3√6xy pls give my answer ace. or expert
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Answer 1

Answer:

Step-by-step 2√2x^3 + 3√3y^3 + √5(5 - 3√6xy)

=(√2x)^3 + (√3y)^3 + 5√5 - 3√30xy

=(√2x)^3 + (√3y)^3 + (√5)^3 - 3 × √2x × √3y × √5

Using x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx)

(√2x + √3y + √5)(2x^2 + 3y^3 + 5 - √6xy - √15y - √10x)