Question

factorise 2 x to the cube minus 7 x square + 2 X + 1​

Answer 1

Answer:

Step-by-step explanation:

2x^3 + 7x^2 - 3x - 18

= 2x^3 + ( 4x^2 + 3x^2) + ( 6x - 9x) - 18

= 2x^3 + 4x^2 +3x^2 + 6x - 9x - 18

= 2x^2 ( x + 2) + 3x ( x + 2) - 9(x +2)

= (x + 2) [ 2x^2 + 3x - 9]

= (x +2) [ 2x^2 + 6x - 3x - 9]

= (x +2) [ 2x ( x + 3) - 3(x + 3)]

= (x +2)(x +3)(2x - 3)