Factorise: 2(x+y)^2 - 9(x+y) - 5
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Answered by
277
2(x+y)²-9(x+y)-5
2(x+y)²-10(x+y)+1(x+y)-5
2(x+y)[(x+y)-5]+1[(x+y)-5]
[2(x+y)+1][(x+y)-5]
2(x+y)²-10(x+y)+1(x+y)-5
2(x+y)[(x+y)-5]+1[(x+y)-5]
[2(x+y)+1][(x+y)-5]
TheGreatPranjalSingh:
solve completely
Answered by
135
Answer:
2( x + y )² - 9( x + y ) - 5 = ( x + y - 5 ) ( 2x + 2y + 1 )
Step-by-step explanation:
Given Expression: 2( x + y )² - 9( x + y ) - 5
We have to factorize it.
Let, x + y = z
we have
2z² - 9z - 5
= 2z² -10z + z - 5
= 2z( z - 5 ) + 1 ( z - 5 )
= ( z - 5 ) ( 2z + 1 )
Now putting back value of z, we get
= ( x + y - 5 ) ( 2(x+y) + 1 )
= ( x + y - 5 ) ( 2x + 2y + 1 )
Therefore, 2( x + y )² - 9( x + y ) - 5 = ( x + y - 5 ) ( 2x + 2y + 1 )
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