factorise:
2(x+y)^2-9(x+y)-5 this is my question.
Answers
Answered by
26
Given
factorise:
2(x+y)^2-9(x+y)-5
Solution
= 2(x + y)² - 9(x + y) - 5
= (x + y) [2(x+y)-9×1-5]
= (x + y) [2x + 2y - 9 - 5]
= (x + y) [2x + 2y - 14]
Important identities
- (a+b)² = a² + b² +2ab
- (a-b)² = a² + b² - 2ab
- (a+b)³ = a³ + b³ + 3ab(a+b)
- (a-b)³ = a³ -b³ - 3ab(a-b)
- a² - b² = (a+b)(a-b)
- a³ + b³ = (a+b)(a² - ab +b²)
- a³ - b³ = (a-b)(a² + ab +b²)
Answered by
2
Given
factorise:
2(x+y)^2-9(x+y)-5
Solution
= 2(x + y)² -9(x + y) - 5
= (x + y) [ 2(x +y) - 9 - 5]
= (x + y) [2x + 2y - 14]
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