Factorise 2(x+y) ^3-6(z+y)
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Hey dear!
Here is yr answer......
=> 2(x+y)³ - 6(z+y)
[ (x+y)³ = x³+3x²y+3xy²+y³ ]
=> 2(x³+3x²y+3xy²+y³) - 6z + 6y
=> 2(x³+3x²y+3xy²+y³ - 3z + 3y)
Hope it hlpz....
Here is yr answer......
=> 2(x+y)³ - 6(z+y)
[ (x+y)³ = x³+3x²y+3xy²+y³ ]
=> 2(x³+3x²y+3xy²+y³) - 6z + 6y
=> 2(x³+3x²y+3xy²+y³ - 3z + 3y)
Hope it hlpz....
tejasri2:
factorise it
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