Question

factorise 2 x² + y² + 8 z² + 2√2x y + 4√2yz + 8 z x​

Answer 1

Step-by-step explanation:

: The answer is (-\sqrt2x+y+2\sqrt2z)(-\sqrt2x+y+2\sqrt2z).(−

2

x+y+2

2

z)(−

2

x+y+2

2

z). )

Step-by-step explanation: We are given to factorise the following expression:

E=2x^2+y^2+8z^2-2\sqrt2xy+4\sqrt 2yz-8xz.E=2x

2

+y

2

+8z

2

−2

2

xy+4

2

yz−8xz.

We will be using the following factorisation formula:

(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca.(a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca.

We have

\begin{gathered}E\\\\=2x^2+y^2+8z^2-2\sqrt2xy+4\sqrt 2yz-8xz\\\\=(-\sqrt2x)^2+y^2+(2\sqrt2z)^2+2(-\sqrt2x)y+2y(2\sqrt2z)+2(2\sqrt2z)(-\sqrt2x)\\\\=(-\sqrt2x+y+2\sqrt2z)^2\\\\=(-\sqrt2x+y+2\sqrt2z)(-\sqrt2x+y+2\sqrt2z).\end{gathered}

E

=2x

2

+y

2

+8z

2

−2

2

xy+4

2

yz−8xz

=(−

2

x)

2

+y

2

+(2

2

z)

2

+2(−

2

x)y+2y(2

2

z)+2(2

2

z)(−

2

x)

=(−

2

x+y+2

2

z)

2

=(−

2

x+y+2

2

z)(−

2

x+y+2

2

z).

Thus, the answer is (-\sqrt2x+y+2\sqrt2z)(-\sqrt2x+y+2\sqrt2z).(−

2

x+y+2

2

z)(−

2

x+y+2

2

z).

Answer 2

Answer:

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