Question

factorise 2 y cube + y square - 2y -1​

Answer 1

Answer:

(y²-1)(2y+1)

Step-by-step explanation:

2y³ + y² - 2y - 1

2y³ + 2y² - y² -y - y -1

2y²(y+1) - y(y+1) -1(y+1)

(y+1)(2y² - y - 1)

(y+1)(2y² - 2y+y - 1)

(y+1)[2y(y-1) + 1(y-1)]

(y+1)(2y+1)(y-1)

(y²-1)(2y+1)

Answer 2

Step-by-step explanation:

$2 y {}^{3} + y {}^{2} - 2y -1$

$= > (2y {}^{3} + y {}^{2} ) + ( - 2y - 1)$

$= > - ( 2y + 1) + y {}^{2} (2y + 1)$

$= > (2y + 1)(y {}^{2} - 1)$

$= >(2y + 1)(y + 1)(y - 1)$

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