factorise 2 y square + 3 Y + 1
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✦ Given ✦
2y² + 3y + 1
Factories it
✦ Solution ✦
✞ Solve this by splitting middle term
→ 2y² + 3y + 1
→ 2y² + 2y + y + 1
→ 2y(y + 1)+1(y + 1)
→ (y + 1)(2y + 1)
✦ Some Identities ✦
- (a+b)² = a² + b² +2ab
- (a-b)² = a² + b² - 2ab
- (a+b)³ = a³ + b³ + 3ab(a+b)
- (a-b)³ = a³ -b³ - 3ab(a-b)
- a² - b² = (a+b)(a-b)
- a³ + b³ = (a+b)(a² - ab +b²)
- a³ - b³ = (a-b)(a² + ab +b²)
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