factorise 20 - 45(m+n)^2
and the answer is
5(2-3m-3n) (2+3m+3n)
please tell me how solve
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Answer:
20-45(m+n)^2
=5{4-9(m+n)^2}
=5{(2)^2-3(m+n)^2}
=5{(2)^2-(3m+3n)^2}
=5(2+3m+3n)(2-3m-3n)
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