factorise 20a^2-45b^2
Answers
Answered by
26
Here is your Answer,
By Using identity ,
a²-b²= ( a+b)(a-b)
Given , = 20a²-45b²
It can be written as ,
= (2√5a)²-(3√5b)²
Here a= (2√5a)
b= (3√5b)
= (2√5a - 3√5b)(2√5a +3√5b)
Hope this helps you....✌^_^
By Using identity ,
a²-b²= ( a+b)(a-b)
Given , = 20a²-45b²
It can be written as ,
= (2√5a)²-(3√5b)²
Here a= (2√5a)
b= (3√5b)
= (2√5a - 3√5b)(2√5a +3√5b)
Hope this helps you....✌^_^
Answered by
54
20a²-45b²
=5(4a²-9b²)
=5[(2a)²-(3b)²]
=5(2a+3b)(2a-3b)
ANS:- 5(2a+3b)(2a-3b)
=5(4a²-9b²)
=5[(2a)²-(3b)²]
=5(2a+3b)(2a-3b)
ANS:- 5(2a+3b)(2a-3b)
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