Question

factorise 20x^2 +3x-56​

Answer 1

Answer:

$20x^2+3x-56= (5x-8)(4x+7)$

Step-by-step explanation:

$20x^2+3x-56\\\\= 20x^2+35x-32x-56\\\\= 5x(4x+7)-8(4x+7)\\\\= (5x-8)(4x+7)$

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Answer 2

Step-by-step explanation:

20x^2+3x-56

=20x^2+x(35-32)-56

=20x^2+35x-32x-56

=5x(4x+7)-8(4x+7)

=(5x-8) (4x+7)