factorise 216 x³ + 1 / 125
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21
216x³+ 1/125
=(6x)³ +(1/5)³
=(6x+1/5)[(6x)² -6x/5 +(1/5)²]
=[6x+(1/5)][36x² -(6x/5) +(1/25)]
=(6x)³ +(1/5)³
=(6x+1/5)[(6x)² -6x/5 +(1/5)²]
=[6x+(1/5)][36x² -(6x/5) +(1/25)]
lakshmi5:
thanks buddy
my pleasure miss :)
Answered by
8
216x³+ 1/125
=(6x)³ +(1/5)³
=(6x+1/5)[(6x)² -6x/5 +(1/5)²]
=[6x+(1/5)][36x² -(6x/5) +(1/25)]
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