Math, asked by thakursi758, 10 months ago

factorise :
216a³+ 1

Answers

Answered by menishray13

4

Answer:

= 216a^3+1

= (6a)^3 + (1)^3

= (6a+1)(6a+1)(6a+1)

Answered by Anonymous

38

${\purple{\fbox{\fbox{\fbox{\mathscr{\orange{Question:}}}}}}}$

↪ Factorise : 216a³+1

${\purple{\fbox{\fbox{\fbox{\mathscr{\orange{Answer:}}}}}}}$

➡ 216a³+1

➡ (6a)³+(1)³

➡ (6a+1){(6a)²-6a×1+(1)²}

➡ (6a+1)(36a²-6a+1)

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Formula used::

a³+b³ = (a+b)(a²-ab+b²)

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