Factorise 216a3+343b3+756a2b+882ab2
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see,
we know that,
(a+b)³=a³+b³+3a²b+3ab²
so in the given we can clearly see that it is in the form of the above identity..
therefore the above can be factorized as,
216a³=(6a)³
343b³=(7b)³
756a²b=3(36a²)(7b)
882ab²=3(6a)(7b)²
therefore it can be written as..
=> (6a+7b)³
Hope it helps.....
we know that,
(a+b)³=a³+b³+3a²b+3ab²
so in the given we can clearly see that it is in the form of the above identity..
therefore the above can be factorized as,
216a³=(6a)³
343b³=(7b)³
756a²b=3(36a²)(7b)
882ab²=3(6a)(7b)²
therefore it can be written as..
=> (6a+7b)³
Hope it helps.....
mrigansh:
pls make it the brainliest answer i really need it..thanks..
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