Question

factorise 24x^3-81y^3​

Answer 1

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Answer 2

Step-by-step explanation:

It can be written as

= 3(8x³-27y³)

By carrying out 3 as common

= Now by using the identity of

a³-b³= (a-b)³+3ab(a-b)

We get

where a= 2x and b= 3y

Now substituite this value of a and b in the formula

= 3((2x-3y)³+3(2x)(3y)(2x-3y))

= 3((2x-3y)³+18xy(2x-3y))

= 3(2x-3y)((2x-3y)²+18xy)

Hope this helps you