Question

factorise 25+10a+a² into factors

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urgently needed
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Answer 1

may be it's help u dear.....syd aapko shii solution mil gya hoo

Answer 2

Step-by-step explanation:

a

2

−10a+25

=a

2

−5a−5a+25, split middle term so that resultant is same

=(a

2

−5a)+(−5a+25), group pair of terms

=a(a−5)−5(a−5), factor each binomials

=(a−5)(a−5), factor out common factor (a−5)

=(a−5)

2