Math, asked by user070, 15 days ago

factorise 25( 3a+ 2b)^2 - 16 ( 3a-2b)^2

Answers

Answered by ItzGamerGG
2

Answer:

Taking (3a + 2b) = x

25x² - 16x²

(5x)² - (4x)²

We know a² - b² = (a + b)(a - c)

(5x - 4x)(5x + 4x)

(5(3a + 2b) - 4(3a + 2b))(5(3a + 2b) + 4(3a + 2b))

(15a + 1Ob - 12a + 8b)(15a + 1Ob + 12a + 8b)

(3a + 18b)(25a + 22b)

3(a + 6b)(25a + 22b) ( Answer )

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Answered by sanjanashrestha37
0

Answer:

factorise 1-25×(2-3a)² ?

Step-by-step explanation:

= (1)2 – [5(a + b)]2

= [1 + 5(a + b)] [1 – 5(a + b)]

= (1 + 5a + 5b) (1 – 5a – 5b)

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