Question

Factorise 25-(4a^2+12a+9)​

Answer 1

Answer:

25-(4a^+12a+9)=0

25-4a^-12a-9=0

-4a^-12a+16=0

0=4a^+12a-16

4a^+12a-16=0

4a^+(16-4)a-16=0

4a^+16a-4a-16=0

4a(a+4)-4(a+4)=0

(a+4)(4a-4)=0

a=-4 or a=4/4=1.

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Answer 2

Answer:

(5+2a+3)(5-2a-3)

Step-by-step explanation:

25-(4a+12a+9)

25-[2a(2a+3)3(2a+3)]

25-(2a+3)(2a+3)

25-(2a+3)^2

5^2-(2a+3)^2

(5+2a+3)(5-2a-3)