factorise 25-p^2-q^2-2pq
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Answered by
47
25 - p^2 - q^2 - 2pq
= (5)^2 - [ p^2 + q^2 + 2pq]
= (5)^2 - [ (p)^2 +(q)^2 +2(p)(q)]
= (5)^2 - (p+q)^2
= (5+p+q)(5-p-q)
= (5)^2 - [ p^2 + q^2 + 2pq]
= (5)^2 - [ (p)^2 +(q)^2 +2(p)(q)]
= (5)^2 - (p+q)^2
= (5+p+q)(5-p-q)
Answered by
49
Nice question mate!!! ✌✌✌
Ur answer goes like this.
》 25 - p^2 - q^2 - 2pq
》 (5)^2 - ( p^2 + q^2 + 2pq)
》 (5)^2 - (p+q)^2
》 (5+p+q)(5-p-q)
☺ Hope this Helps ☺
If u find it as most helpful pls mark it as brainliest.
Ur answer goes like this.
》 25 - p^2 - q^2 - 2pq
》 (5)^2 - ( p^2 + q^2 + 2pq)
》 (5)^2 - (p+q)^2
》 (5+p+q)(5-p-q)
☺ Hope this Helps ☺
If u find it as most helpful pls mark it as brainliest.
nitthesh7:
Tan q for brainliest
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