Factorise 25(x-2y)^2-4
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25(x-2y)^2 - 4
{5(x-2y)}^2 - 4
{5(x-2y)}^2 - (2)^2
Since a^2 - b^2 = (a+b) (a-b)
= [{5(x-2y)} + 2] [{5(x-2y)} - 2]
= (5x - 10y +2) ( 5x - 10y - 2).
{5(x-2y)}^2 - 4
{5(x-2y)}^2 - (2)^2
Since a^2 - b^2 = (a+b) (a-b)
= [{5(x-2y)} + 2] [{5(x-2y)} - 2]
= (5x - 10y +2) ( 5x - 10y - 2).
Anonymous:
Thnx
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