factorise 25 x²-9a²+6ay-y²
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Answer:
25x
2
+16y
2
+4z
2
−40xy+16yz−20xz
= (−5x)
2
+(4y)
2
+(2z)
2
+2(−5x)(4y)+2(4y)(2z)+2(−5x)(2z)
Suitable identities is (x+y+z)
3
=x
3
+y
3
+z
3
+2xy+2yz+2xz
Therefore, (−5x)
2
+(4y)
2
+(2z)
2
+2(−5x)(4y)+2(4y)(2z)+2(−5x)(2z)
= (−5x+4y+2z)
2
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