Question

Factorise : - 256 x to the power 16 - 1




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Answer 1

Answer:

256x^16-1

=> (16x^8)^2-1^2

=> (16x^8+1)(16x^8-1)

=> (16x^8+1)[(4x^4)^2-1^2)]

=> (16x^8+1)(4x^4+1)(4x^4-1)

=> (16x^8+1)(4x^4+1)[(2x^2)^2-1^2]

=> (16x^8+1)(4x^4+1)(2x^2+1)(2x^2-1)

Answer 2

$\huge\purple{Answer:-}$

256x^16-1

=> (16x^8)^2-1^2

=> (16x^8+1)(16x^8-1)

=> (16x^8+1)[(4x^4)^2-1^2)]

=> (16x^8+1)(4x^4+1)(4x^4-1)

=> (16x^8+1)(4x^4+1)[(2x^2)^2-1^2]

=> (16x^8+1)(4x^4+1)(2x^2+1)(2x^2-1)