Question

Factorise:25a^2-9b^2+12bc-4c^2

Answer 1

Answer:

(5a+3b-2c)(5a-3b+2c)

Step-by-step explanation:

25a2 -( 9b2-12bc+4c2)

= (5a)2 - {(3b)2 - 2*3b*2c+ (2c)2}

=(5a)2 - (3b-2c)2

=(5a+3b-2c)(5a-3b+2c)

If you don't mind me asking, are you student of ICSE class 9??

Answer 2

(5a+3b-2c) (5a-3b+2c)

Step-by-step explanation:

25a^2-9b^2+12bc-4c^2

= 25a^2 - {9b^2 + 4c^2 - 12bc}

= {(5a)^2 - (3b)^2 + (2c)^2 - 2 * 3b * 2c}

= (5a)^2 - (3b - 2c)^2

by using the identity {(a - b)^2 = (a^2 + b^2 - 2ab)}

= {5a + (3b - 2c)} {5a - (3b - 2c)}

by using the identity {a^2 - b^2 = (a + b) (a - b)}

= (5a + 3b - 2c) (5a - 3b + 2c)

Learn more: factorize

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