Question

factorise 25p2 _ 36q2​

Answer 1

$\red{ \huge{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: SOLUTION \: \: \red{ \mid}}}}}}}}$

$\bold{25p {}^{2} - 36q {}^{2} } \\ \\ \bold{ = (5p) {}^{2} - (6q) {}^{2} } \\ \\ \\ \underline{\bold{ \: \: Using \: \: \red {x {}^{2} - y {}^{2} = (x + y)(x - y)} \: \: formula \: \: }} \\ \\ \\ \bold{ = (5p) {}^{2} - (6q) {}^{2} } \\ \\ \bold{ = (5p + 6q)(5p - 6q)} \\ \\ \\ \underline{\bold{\therefore \: \: 25p {}^{2} - 36q {}^{2} = (5p+6q)(5p-6q)}}$

Answer 2

Answer:

25p2 _ 36q2​ = (5p + 6q)(5p - 6q)

Step-by-step explanation:

• Given expression is 25p2 _ 36q2​

• We notice that the expression is a difference of two perfect squares.

        ∴  It is in the form of x2 - y2

Now, 25p2 _ 36q2​

         = $(5p) ^{2}$ - $(6q)^{2}$...............................................(i)

• Hence Identity  , $x^{2}$ - $y^{2}$= (x + y)(x - y) can be applied in the given expression.

• Applying this formula in equation (i), we get

       $(5p)^{2}$ - ($6q^{2}$) = (5p + 6q)(5p - 6q)

• So, the factors are (5p + 6q), (5p - 6q)