Question

Factorise: 25x^-36y^

Answer 1

Answer:

Step-by-step explanation:

i think the question is 25x^2-36^2

by adding roots

= 5x-6y

Answer 2

$\large\sf\underline{Correct\:question\::}$

• Factorise : $\sf\:25x^{2}-36y^{2}$

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$\large\sf\underline{Given\::}$

• $\sf\:25x^{2}-36y^{2}$

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$\large\sf\underline{To\::}$

• Factorise the given expression.

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$\large\sf\underline{Solution\::}$

$\sf\:25x^{2}-36y^{2}$

We will use one identity that is :

$\large{\underline{\boxed{\mathrm\green{a^{2}-b^{2}=(a+b)(a-b)}}}}$

$\sf\implies\:(5x)^{2}-(6y)^{2}$

Here ,

• a = 5x

• b = 6x

So let's substitute the value of a and b in the identity :

${\sf{{\purple{\implies\:(5x+6y) (5x-6y)}}}}$${\sf{{\red{★}}}}$

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$\large\sf\underline{Some\:more\:identity\::}$

• $\sf\:(a+b)^{2}=a^{2}+2ab+b^{2}$

• $\sf\:(a-b)^{2}=a^{2}-2ab+b^{2}$

• $\sf\:a^{2}-b^{2}=(a+b) (a-b)$

• $\sf\:(a+b+c)^{2}=a^{2}+b^{2}+c^{2}+2ab+2bc+2ca$

• $\sf\:(a+b)^{3}=a^{3}+b^{3}+3ab(a+b)$

• $\sf\:(a-b)^{3}=a^{3}-b^{3}-3ab(a-b)$

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!! Hope it helps !!