Factorise: 25x2 - 10x + 1 - 36y2
Answers
Answer:
Answer: By factorization of \bold{25 x^{2}-10 x+1-36 y^{2}}25x
2
−10x+1−36y
2
,we get ((5x-1) + 6y) ((5x-1) - 6y)
25 x^{2}-10 x+1-36 y^{2}=(5 x)^{2}-2(5 x)+1^{2}-(6 y)^{2}25x
2
−10x+1−36y
2
=(5x)
2
−2(5x)+1
2
−(6y)
2
We know that by formula, (a-b)^{2}=a^{2}+b^{2}-2ab(a−b)
2
=a
2
+b
2
−2ab
(5 x)^{2}-2(5 x)+1^{2}(5x)
2
−2(5x)+1
2
can be written as (5 x-1)^{2}(5x−1)
2
25 x^{2}-10 x+1-36 y^{2}=(5 x-1)^{2}-(6 y)^{2}25x
2
−10x+1−36y
2
=(5x−1)
2
−(6y)
2
We know that by formula, a^{2}-b^{2}=(a+b)(a-b)a
2
−b
2
=(a+b)(a−b)
Hence 25 x^{2}-10 x+1-36 y^{2}25x
2
−10x+1−36y
2
= ((5x
Step-by-step explanation:
For any future discussions follow and dm me on insta: _kaushik_9753dk_
Answer:
(5x)²_2×5x×1+ (1)²_(6y)²
=(5x_1)²_(6y)²
Now ,on a²_b²=(a+b)(a_b)
so,(5x_1+6y)(5x_1_6y)...........Answer