Factorise 25x³y³-49xy
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we have to take 25 as 5 to the power 2 and -49 as -7 to the power 2
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ANSWER:
- Factorisation of the above expression is xy(5xy+7)(5xy-7)
GIVEN:
- P(x) = 25x³y³ - 49xy
TO FIND:
- Factorise the above expression.
Formula used:
- a²-b² = (a+b)(a-b)
SOLUTION:
= 25x³y³ - 49xy
= xy (25x²y²-49)
= xy [(5xy)²-(7)²]
= xy(5xy+7)(5xy-7)
Factorisation of the above expression is xy(5xy+7)(5xy-7)
NOTE:
Some important formulas:
(a+b)² = a²+b²+2ab
(a-b)² = a²+b²-2ab
(a+b)(a-b) = a²-b²
(a+b)³ = a³+b³+3ab(a+b)
(a-b)³ = a³-b³-3ab(a-b)
a³+b³ = (a+b)(a²+b²-ab)
a³-b³ = (a-b)(a²+b²+ab)
(a+b)² = (a-b)²+4ab
(a-b)² = (a+b)²-4ab
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