factorise 25xsquare + 16ysquare + 4zsquare -40xy+ 16yz-20xz
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let us take 5x to be negative
it can be written as
(-5x)^2+(4y)^2+(2z)^2+(2)(-5x)(4z)+(2)(4y)(2z)+(2)(-5x)(2z)
this is in the form of a^2+b^2+c^2+2ab+2bc+2ca
where a=-5x
b=4y
c=2z
so this is equal to
a^2+b^2+c^2+2ab+2bc+2ca=(a+b+c)^2
in this case it is equal to
(5x+4y+2z)^2
hope this helps you
pls mark brainliest
it can be written as
(-5x)^2+(4y)^2+(2z)^2+(2)(-5x)(4z)+(2)(4y)(2z)+(2)(-5x)(2z)
this is in the form of a^2+b^2+c^2+2ab+2bc+2ca
where a=-5x
b=4y
c=2z
so this is equal to
a^2+b^2+c^2+2ab+2bc+2ca=(a+b+c)^2
in this case it is equal to
(5x+4y+2z)^2
hope this helps you
pls mark brainliest
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