Factorise (25y² + 40 + 16) and divide by (5y + 4)
Answers
Answer:
your question is somewhat wrong
Simplifying
25y2 + 40y + 16 = 0
Reorder the terms:
16 + 40y + 25y2 = 0
Solving
16 + 40y + 25y2 = 0
Solving for variable 'y'.
Factor a trinomial.
(4 + 5y)(4 + 5y) = 0
Subproblem 1
Set the factor '(4 + 5y)' equal to zero and attempt to solve:
Simplifying
4 + 5y = 0
Solving
4 + 5y = 0
Move all terms containing y to the left, all other terms to the right.
Add '-4' to each side of the equation.
4 + -4 + 5y = 0 + -4
Combine like terms: 4 + -4 = 0
0 + 5y = 0 + -4
5y = 0 + -4
Combine like terms: 0 + -4 = -4
5y = -4
Divide each side by '5'.
y = -0.8
Simplifying
y = -0.8
Subproblem 2
Set the factor '(4 + 5y)' equal to zero and attempt to solve:
Simplifying
4 + 5y = 0
Solving
4 + 5y = 0
Move all terms containing y to the left, all other terms to the right.
Add '-4' to each side of the equation.
4 + -4 + 5y = 0 + -4
Combine like terms: 4 + -4 = 0
0 + 5y = 0 + -4
5y = 0 + -4
Combine like terms: 0 + -4 = -4
5y = -4
Divide each side by '5'.
y = -0.8
Simplifying
y = -0.8
Solution
y = {-0.8, -0.8}
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