Question

factorise 27-125x^3-135x+225x^2

Answer 1

remember the identity
$( {a - b)}^{3} = ( {a}^{3} - {b}^{3} - 3 {a}^{2} b + 3a {b}^{2} ) \\ try \: to \: apply \: this \: identity \: in \: your \: question \\ {(3)}^{3} - ( {5x)}^{3} - 3( {3)}^{2} (5x) + 3(3)( {5x)}^{2} \\ = 27 - 125 {x}^{3} - 135x + 225 {x}^{2} \\ is \: equal \: to \: given \: polynomial \\ so \:this \: can \: be \: written \: as \\ ( {3 - 5x)}^{3} are \: the \: factors \: of \: given \: polynomial$

Answer 2

Answer:

(3-5x)³

Step-by-step explanation:

$27 - 125x^{3} - 135x +225x^{2} \\= (3)^{3}-(5x)^{3}-3(3)^{2}(5)+3(3)(5)^{2}\\\\Using: (a-b)^{3}=(a^{3} - b^{3} - 3a^{2}b + 3ab^{2})\\\\(3-5x)^{3}$

Hope this helped!!!