Math, asked by krushantptl, 1 year ago

factorise 27×^3+y^3^3-9×yz

Answers

Answered by sapanaojha
0
[27x ^{3} + y ^{3} + z ^{3} - 3xyz = 0
(27x) ^{3} + y ^{3 } + z ^{3} = 3xyz
(3x + y + z) ^{3}
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