factorise 27×^3+y^3^3-9×yz
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[27x ^{3} + y ^{3} + z ^{3} - 3xyz = 0
(27x) ^{3} + y ^{3 } + z ^{3} = 3xyz
(3x + y + z) ^{3}
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(27x) ^{3} + y ^{3 } + z ^{3} = 3xyz
(3x + y + z) ^{3}
plz mark it as brainliest
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