factorise 27^a3 - (3a-b)3
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Answered by
1
Hey mate!
Here is your answer > >
27a^3-(3a-b)^3
(3a)^3-(3a-b)^3
(a)^3-(b)^3=(a-b)(a^2+b^2+ab)
(3a-3a+b)[(3a)^2+(3a-b)^2+(3a)(3a-b)]
b (9a^2+9a^2+b^2-6ab+9a^2-3ab)
b (27a^2+b^2-9ab)
Hope it helps!
Thankyou ☆ ☆
Here is your answer > >
27a^3-(3a-b)^3
(3a)^3-(3a-b)^3
(a)^3-(b)^3=(a-b)(a^2+b^2+ab)
(3a-3a+b)[(3a)^2+(3a-b)^2+(3a)(3a-b)]
b (9a^2+9a^2+b^2-6ab+9a^2-3ab)
b (27a^2+b^2-9ab)
Hope it helps!
Thankyou ☆ ☆
Answered by
5
hope you understand
it is step by step
BE BRAINLY
it is step by step
BE BRAINLY
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