Question

factorise 27 a³+8b³+ c³ - 18 abc​

Answer 1

Answer:

=(3a)^3+(2b)^3+(c)^3-3×3a×2b×c

=(3a+2b+c) {(3a)^2+(2b)^2+(c)^2-3a×2b-2b×c-c×3a}

=(3a+2b+c)(9a^2+4b^2+c^2-6ab-2bc-3ac)

Answer 2

hope it's helpful mark it as brainliest I personally solved it