factorise 27(m+2n) cube +(m-6n)cube
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Answer:
27(m + 2n)3 +(m - 6n)3
= [3(m + 2n)3] + (m - 6n)3
= [3(m + 2n) + m - 6n][9(m + 2n)2 - 3(m + 2n)(m - 6n) + (m - 6n)2]
= (3m + 6n + m - 6n)[9(m2 + 4mn + 4n2 - 3(m2 - 6mn + 2mn - 12n2) + m2 - 12mn + 36n2)]
= 4m (9m2 + 36mn + 36n2 - 3m2 + 18mn - 6mn + 36n2 + m2 - 12mn + 36n2)
= 4m(7m2 + 36mn + 108n2)
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