Psychology, asked by afisalady4373, 8 months ago

Factorise 27 x^3-(3 x-y)^3

Answers

Answered by suggulachandravarshi

0

Answer:

(3x)^3-(3x-y)^3

= [3x-(3x-y)][(3x)^2+3x(3x-y)+(3x-y)^2]

=(3x-3x+y)[9x^2+9x^2-3xy+9x^2-6xy+y2]

=(y)[27x^2-9xy+y^2].

Hope it helps you....

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